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Solving Exponential and Logarithmic Equations In Exercise, solve for x.
2 In x + In(x - 2) = 0

User Milo Bem
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1 Answer

3 votes

Answer:

The value of x is about 2.206.

Explanation:

Consider the given equation is


2\ln x+\ln (x-2)=0

We need to find the value of x.

Using the properties of logarithm we get


\ln x^2+\ln (x-2)=0
[\because \ln a^b=b\ln a]


\ln (x^2(x-2))=0
[\because \ln (ab)=\ln a+\ln b]


\ln (x^2(x-2))=ln 1
[\because \ln 1=0]

On comparing both sides we get


x^2(x-2)=1


x^3-2x^2=1

Using graphing calculator, the real solution of the above equation is


x\approx 2.206

Therefore, the value of x is about 2.206.

User Kasun Gajasinghe
by
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