Question

Graphing Natural Exponential Functions In Exercise, sketch the graph of the function.

g(x) = e2x - 1

Answer 1

Let
`g(x)=e^(2x-1)`

View Graph

Explanation:

Let
`g(x)=e^(2x-1)`

find the cutting points with respect to the axes.

We can say that g(x) = y, well then
`y=e^(2x-1)`, if x=0 then
`y=e^(2x-1)=e^((2*0-1))=e^(-1)=0.36787`

with respect to x there are no cut points since it is an asymptote

To x=1 y≅2.718, x=-1 y≅0.049, x=2 y≅20.08, x=-2 y≅0.0067, this for plotting some values