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Find the average value of f(x) = √x+1 over the interval [0, 8].

User Blackgrid
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1 Answer

3 votes

The average value of
f(x) over [0, 8] is


\displaystyle\frac1{8-0}\int_0^8√(x+1)\,\mathrm dx=\frac1{12}(x+1)^(3/2)\bigg|_0^8=\frac{13}6

User Ilya Volodin
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