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Suppose that instead of using natuarl logarithma to compute b, we use logarithms with the base 10 and define b=(log r)/(log 2). Does this change the value of b?

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Answer:

Yes it changes the value of b.

Explanation:

Natural log is log with base e = 2.71828.


ln(2)=log_(e)(2)=0.693\\\\where as\\\\log_(10)(2)=0.301\\

From this we can conclude that value b when calculated with log to base 10 instead of natural log, value of b will change.

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