Question

Calculate You place a 0.18-kg can of soup and a 0.34-kg Jar of pickles on the kitchen counter, separated by a distance of 0.42 m. What is the magnitude of the force of gravity that (a) the can of soup exerts on the jar of pickles and (b) the jar exerts on the can?

Answer 1

pickles and (b) the jar exerts on the can

Step-by-step explanation:

pickles and (b) the jar exerts on the can

Answer 2

Step-by-step explanation:

Given that,

Mass of can soup,
`m_1=0.18\ kg`

Mass of jar of pickles,
`m_2=0.34\ kg`

The distance between these two objects, d = 0.42 m

There exists a force of gravity between the can of soup and the jar of pickles. This force is given by :

`F=(Gm_1m_2)/(d^2)`

`F=(6.67* 10^(-11)* 0.18* 0.34)/((0.42)^2)`

`F=2.31* 10^(-11)\ N`

(a) So, the force of gravity the can of soup exerts on the jar of pickles is
`F=2.31* 10^(-11)\ N`.

(b) The force of gravity the jar exerts on the can is also
`F=2.31* 10^(-11)\ N` due to the Newton's third law of motion.