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Determine the radius of convergence of the following power series. Then test the endpoints to determine the interval of convergence.

Σ(21x)^k

The radius of convergence is R =______

a. The interval of convergence is {x: x=______ }
b. The Interval of convergence is:______

1 Answer

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Answer:

Radius of the convergence is R =
(1)/(21)

and,

The Interval of convergence is
-(1)/(21)<x<(1)/(21)

Explanation:

Given function : Σ(21x)^k

Now,

Using the ratio test, we have

R =
\lim_(n \to \infty) |(21x^(k+1))/(21x^(k))|

or

R =
\lim_(n \to \infty) |(21x^(k)*21x^(1))/(21x^(k))|

or

R =
\lim_(n \to \infty) |21x^(1)|

now,

for convergence R|x| < 1

Therefore,


\lim_(n \to \infty) |21x^(1)| < 1

or


-(1)/(21)<x<(1)/(21)

and,

Radius of the convergence is R =
(1)/(21)

and,

The Interval of convergence is
-(1)/(21)<x<(1)/(21)

User Dreamr OKelly
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