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The Caesar Cipher has 25 different shifts to try. How many possibilities are there to try in a random substitution cipher

User Hitfactory
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1 Answer

1 vote

Answer: 26! or
\approx 4.03*10^(26)

Explanation:

  • The Caesar Cipher is an encoding method that shifts alphabets.
  • The random substitution is an encoding method that move each letter of the alphabet randomly to different .

Given : The Caesar Cipher has 25 different shifts to try.

Since the total a letters in the English Alphabet = 26

Then, the number of possibilities in a random substitution cipher =
26!


=26*25*24*23*...*3*2*1\\\\=4.03*10^(26)

Hence, there are 26! ( or
\approx 4.03*10^(26)) possibilities to try in a random substitution cipher .

User Justin Meltzer
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5.1k points