Question

Determine whether the results appear to have statistical​ significance, and also determine whether the results appear to have practical significance. In a study of a gender selection method used to increase the likelihood of a baby being born a​ girl, 2031 users of the method gave birth to 994 boys and 1037 girls. There is about anan 18​% chance of getting that many girls if the method had no effect.

Answer 1

See explanation below.

Explanation:

Assuming this question : "Because there is a 18% chance of getting that many girls by​ chance, the method ______________.

_________ couples would likely use a procedure that raises the likelihood of a girl from the approximately​ 50% rate expected by chance to the ____​% produced by this method.

​(Round to the nearest integer as​ needed.)

So this method _____________ "

Solution to the problem

First we can find the proportion of grils and boys in the sample

`P_(boys)= (994)/(2031)=0.489`

`P_(girls)=(1037)/(2031)=0.511`

For the first blank space we have this:

Because there is a 18% chance of getting that many girls by​ chance, the method does not have statistical significance. (The reason is because we need to have >50% in order to have statistical significance in order to increase the likehoog of a baby being born as girl, since from theory the original probability that a baby would be girl is 0.5 or 50%)

For the next paragraph we have:

Not many couples would likely use a procedure that raises the likelihood of a girl from the approximately​ 50% rate expected by chance to the 51​% produced by this method.

And for the last paragraph we have this:

So this method does not have practical significance (Because not increase as the expected results the probability that a baby would be girl)