Answer:
Oxygen is the limiting reactant
Step-by-step explanation:
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
2moles of hydrogen will require 1mol of oxygen to produce 2mol of water
in the question, 6.45g of O2 reacts with 1.13g of H2.
molar mass of O2 = 16*2 =32g/mol
molar mass of H2 = 1*2=2g/mol
number of moles of O2 = mass/molar mass
= 6.45/32
=0.20156moles
number of moles of H2 = 1.13/2
=0.565moles
but 0.20156moles of O2 will require 0.40312moles of hydrogen
2H2 + O2 ⇒ 2H2O
2mol 1mol 2mol
0.40312mole 0.20156mol
0.40312moles is less than 0.565moles of H2 present, which means hydrogen is in excess hence implying that oxygen is the limiting reactant