Question

60 points please help me i will appreciate it!

Answer 1

`\huge\boxed{\sf v = 62.7 \ L}`

Step-by-step explanation:

Given Data:

Mole = n = 3.38 mol

Temp = t = 269 K

Pressure = 1.19 atm

Gas constant = R = 0.08206 L atm K⁻¹ mol⁻¹

Required:

Volume = v = ?

Formula:

Pv = nRT

Solution:

Rearranging formula

`\displaystyle v = (nRT)/(P) \\\\v = ((3.38)(0.08206)(269))/(1.19) \\\\v = (74.6)/(1.19) \\\\v = 62.7 \ L\\\\\rule[225]{225}{2}`