Question

0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K. Find Q.? (Unit=J)

Answer 1

The correct answer is -225 J.

Answer 2

The heat exchange in the given process = -806.79 J

Step-by-step explanation:

0.235 moles of a diatomic gas expands doing 205 J of work while the temperature drops 88 K.

Number of moles , n = 0.235

Temperature difference = 88 K

According to conservation of energy,

ΔQ = ΔU + ΔW

We are given the amount of work done and we have to find the heat exchange in the process.

`C_(v) = (7R)/(2)` =
`3.5* 8.314` = 29.1

ΔU =
`n* C_(v)*`ΔT

ΔU =
`0.235* 29.1* (-88)` = -601.79 J

Work done by the gas = -205 J

ΔQ = ΔU + ΔW

Substituting the values,

ΔQ = -601.79 + -205 = -806.79 J

The heat exchange in the given process = -806.79 J