Question

The Lapointe family has 4 kids, 2 boys and 2 girls. Suppose that for each birth, the probability of a boy birth is 1/2, and the probability of a girl birth is also 1/2. What is the fractional probability of having 2 boys and 2 girls, in any order, in a family's first 4 births?

Answer 1

Answer: 3/8

Explanation:

`\text{Let boy be: $ A$} \\$$\text {Let girl be } B \\\\$$\mathrm{$A A B B \ \ A B A B \ \ A B B A \ \ B A A B \ \ B A B A \ \ B B A A} \\\\=$(6)/(16) = \bf{(3)/(8)}`