Question

Given 24.3 g of LICI, Find moles of PbCI, produced.
PbSO4 + LiCl → PbCl2 + Li2SO4

Answer 1

0.29 moles of PbCl₂

Step-by-step explanation:

Given data:

Mass of lithium chloride = 24.3 g

Moles of PbCl₂ = ?

Solution:

Chemical equation;

PbSO₄ + 2LiCl → PbCl₂ + Li₂SO₄

Number of moles of LiCl:

Number of moles = mass/ molar mass

Number of moles = 24.3 g/ 42.394 g/mol

Number of moles = 0.57 mol

Now we will compare the moles of PbCl₂ with LiCl .

LiCl : PbCl₂

2 : 1

0.57 : 1/2×0.57 = 0.29 mol