Answer:
By AAS criteria Δ ABC ≅ Δ ADC
Explanation:
See the diagram attached.
We have to prove Δ ABC ≅ Δ ADC
Steps :
Between Δ ABC and Δ ADC
1. CA bisects ∠ BAD, and hence, ∠ CAB = ∠ CAD {Given}
2. ∠ B = ∠ D {Given}
3. Side AC is common to both the triangles.
Hence, by Angle-Angle-Side i.e. AAS criteria Δ ABC ≅ Δ ADC (Proved)