Question

I need help with this question please

Answer 1

Explanation:

As ABCD is a rectangle, ∠A = 90°.

Diagonal BD will be the hypotenuse.

`Sin \ 53^( \circ) = \sf (opposite \ of \ angle \ 53)/(hypotenuse)\\\\\\0.7986=(AB)/(42.3)\\\\\\0.7986*42.3=AB\\\\\bold{AB = 33.8}`

Length = AB = 33.8 cm

`\sf Cos \ 53^( \circ) =(adjacent \ side \ to \ angle \ 53)/(hypotenuse)\\\\\\0.6018 = (AD)/(42.3)\\\\\\0.6018*42.3 =AD\\\\\bold{AD = 25.5 }`

Width = 25.5 cm