Answer:the price of one advance ticket is $40
the price of one same day ticket is $15
Explanation:
Let x represent the price of one advance ticket.
Let y represent the price of one same day ticket.
The combined cost of one advance ticket and one same-day ticket is $55. This means that
x + y = 55
For one performance, 25 advance tickets and 30 same-day tickets were sold. The total amount paid for the tickets was $1450. This means that
25x + 30y = 1450 - - - - - - - - -1
Substituting x = 55 - y into equation 1, it becomes
25(55 - y) + 30y = 1450
1375 - 25y + 30y = 1450
- 25y + 30y = 1450 - 1375
5y = 75
y = 75/5 = 15
Substituting y = 15 into x = 55 - y, it becomes,
x = 55 - 15
x = 40