Question

a rectangular garden is 7 feet long and 6 feet wide. a second rectangular garden has 3/2 the dimensions of the first garden .what is the percent in change from the first garden to the second garden

Answer 1

125%

Explanation:

Given: First Rectangular garden has dimension of 7 feet long and 6 feet wide.

Second Rectangular garden B has 3/2 the dimensions of the first garden.

Considerdering first garden as "A" and second garden as "B".

First lets find the Area for first rectangular garden.

Formula; Area of rectangle=
`length* width`

Area of Graden A=
`7* 6= 42\ feet`

∴ Area of Garden A is 42 feet.

Now, finding area of Garden B.

As given second rectangular garden has 3/2 the dimensions of the first garden.

∴ Length=
`(3)/(2)* 7= (21)/(2)\ feet`

Width=
`(3)/(2) * 6= 9\ feet`

∴ Area of Garden B=
`(21)/(2) * 9= (189)/(2)`

Area of Garden B= 94.5\ feet

Next, finding percent change from the first garden to the second garden.

Difference in area of garden from A to B=
`94.5\ feet- 42\ feet= 52.5\ feet`

Percent change=
`(difference)/(Area\ of\ first\ area)* 100`

⇒ Percent change=
`(52.5)/(42) * 100= 125\%`

Hence, the percent in change from the first garden to the second garden is 125%.