Question

So I have this question here, can someone please help me?

Answer 1

`\\ \rm\rightarrowtail tan\theta=(Perpendicular)/(Base)`

`\\ \rm\rightarrowtail tan51=(x)/(10)`

`\\ \rm\rightarrowtail x=10tan51`

`\\ \rm\rightarrowtail x=10(1.2348971565350)`

`\\ \rm\rightarrowtail x=12.348971565350`

Answer 2

Use tan trig ratio:

`\sf tan(\theta)=(O)/(A)`

where
`\theta` is the angle, O is the side opposite the angle, and A is the side adjacent the angle

Given:

• 
  `\theta` = 39°
• O = 10
• 
  `x` = A

Substituting these values into the formula:

`\implies \tan(39)=(10)/(x)`

Multiplying both sides by
`x`:

`\implies x\tan(39)=10`

Dividing both sides by
`\tan(39)` :

`\implies x=(10)/(\tan(39))`

`\implies x=12.34897157...`

`\implies x=12.3 \ \textsf{(nearest tenth)}`