Answer:
160
Step-by-step explanation:
Data provided in the question:
Population of fruit flies = 1000
Population with red eyes = 640
Now,
q² for the population = 360 ÷ 1000 = 0.36
or
q = √0.36
or
q = 0.6
Therefore,
p = 1 − q
= 1 - 0.6
= 0.4
Hence,
The homozygous dominant frequency = p² = 0.4 × 0.4
= 0.16
Individuals we would expect to be homozygous for red eye color
= p × population
= 0.16 × 1000
= 160