Question

The sound intensity level 5.0 m from a point source is 95 dB. At what distance will it be 75 dB?

Answer 1

47.86 or 50 m

Step-by-step explanation:

Source = 95 + (20log(5) + 10log(4pi)) = 119.96 dB

75 - 119.96 + 10log(4pi) = -33.61

-33.61/-20 = log(distance)

10^1.68 = distance = 47.86m

47.86 or 50 m is the correct ans