Answer:
The final speed and the displacement of the automobile are 19.3 m/s and 59 m respectively
Explanation:
From Newton's Equation of motion,
a = v-u/t.......................... Equation 1
making v the subject of the equation above,
v = at + u ........................ Equation 2
Where a = acceleration of the automobile, v = final speed, u = initial speed, t = time.
Given:a = 3.00 m/s², u = 4.3 m/s, t = 5.00 s
Substituting these values into equation 2,
v = 3(5) + 4.3
v = 15 + 4.3
v = 19.3 m/s.
Also using
v² = u² + 2as
Making s the subject of the equation,
s = (v²-u²)/2a
Where s = displacement.
Given: v= 19.3 m/s, u = 4.3 m/s, a = 3 m/s²
Substituting these values into equation 2
s = (19.3²-4.3²)/2×3
s = (372.49 - 18.49)/6
s = 354/6
s = 59 m
Thus the final speed and the displacement of the automobile are 19.3 m/s and 59 m respectively