Question

What is the net ionic equation for the reaction that occurs when aqueous copper(II) sulfate is added to excess 6-molar ammonia?a. Cu2+ + SO42¯ + 2 NH4+ + 2 OH¯ ---> (NH4)2SO4 + Cu(OH)2 b. Cu2+ + 4 NH3 + 4 H2O --> Cu(OH)42¯ + 4 NH4+ c. Cu2+ + 2 NH3 + 2 H2O --> Cu(OH)2 + 2 NH4+ d. Cu2+ + 4 NH3 --> Cu(NH3)42+ e. Cu2+ + 2 NH3 + H2O --> CuO + 2 NH4+

Answer 1

c. 2NH₃ + 2H₂O + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

Step-by-step explanation:

A net ionic equation is a chemical equation that list only the species that are involved in the reaction.

The reaction of ammonia with copper(II) sulfate CuSO₄ in water is:

2NH₃ + 2H₂O + CuSO₄ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

In an ionic equation, salts are written as ions, that means CuSO₄ must be written as Cu²⁺ + SO₄²⁻. That is:

2NH₃ + 2H₂O + Cu²⁺ + SO₄²⁻ → Cu(OH)₂(s) + 2NH₄⁺ + SO₄²⁻

As in a net ionic equation you must list only the species involved in the reaction (The underlined species don't react), the net ionic equation is:

c. 2NH₃ + 2H₂O + Cu²⁺ → Cu(OH)₂(s) + 2NH₄⁺

I hope it helps!