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Prove theoretically that opposite angles of a parallelogram are equal​

User Shiyas
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To show that the parallelogram's opposite angles are equal.

Create a parallelogram ABCD by drawing a parallelogram ABCD. Join the BD team.

Proof: ABD and BCD form a triangle.

[opposite sides of the parallelogram] AB = CD

[opposite sides of the parallelogram] BC = DA

BD is a very frequent condition.

As a result, triangles ABD and BCD are identical.

As a result, A = C, with sides opposing BD.

In the same way, B = D.

As a result, the parallelogram's opposite angles are equal.

I hope this helps, even if it's just a little :)

User GrayDwarf
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