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3 votes
In a set of scores with a mean of 50 and a standard deviation of 5, what raw score is represented be a z-score of 1.00?

A. 30
B. 55
C. 60
D. 20

User Loentar
by
4.8k points

1 Answer

3 votes

Answer:

B. 55

Explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean
\mu and standard deviation
\sigma, the zscore of a measure X is given by:


Z = (X - \mu)/(\sigma)

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:


\mu = 50, \sigma = 5

What raw score is represented be a z-score of 1.00?

This is X when Z = 1. So:


Z = (X - \mu)/(\sigma)


1 = (X - 50)/(5)


X - 50 = 5


X = 55

So the correct answer is:

B. 55

User Pkit
by
5.3k points
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