Answer:
B. 55
Explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
![\mu = 50, \sigma = 5](https://img.qammunity.org/2021/formulas/mathematics/college/309ikuv013t32zm34d7w5icc2u8xxfv430.png)
What raw score is represented be a z-score of 1.00?
This is X when Z = 1. So:
![Z = (X - \mu)/(\sigma)](https://img.qammunity.org/2021/formulas/mathematics/college/c62rrp8olhnzeelpux1qvr89ehugd6fm1f.png)
![1 = (X - 50)/(5)](https://img.qammunity.org/2021/formulas/mathematics/college/csn3pzer64lphf775q8gyq0r9c3oipkxoc.png)
![X - 50 = 5](https://img.qammunity.org/2021/formulas/mathematics/college/v2wgvg8a29id5jt3vzstezmi4285rh3li6.png)
![X = 55](https://img.qammunity.org/2021/formulas/mathematics/college/alzvk7346iziabey904sb89bdi7ianpg8d.png)
So the correct answer is:
B. 55