Answer:
The greatest acceleration when the unbalanced force is applied will be experienced in :
A) The box with a mass of 2 kg
Step-by-step explanation:
According to second law of motion the external unbalanced force is directly proportional to rate of change of momentum.
F = (Final momentum - initial momentum)/time
or
Force is equal to the product of mass and acceleration
F = m x a
Here a= acceleration
m = mass of the object
If Force is constant then acceleration is inversely proportional to mass
![a =(F)/(m)](https://img.qammunity.org/2021/formulas/biology/middle-school/p4hm43zm58seiwxlgt3jqck0k0r7ktjbtq.png)
A) The box with a mass of 2kg
F = 8 N
![a =(8)/(2)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/w1t5br1knu3sdssjvthwlxxq2njvx0ncc9.png)
a = 4 m/s2
B) The box with the mass of 4kg
![a =(8)/(4)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/ijqe9il5bfkc9ojcwwasm88wdff0otonax.png)
a = 2 m/s2
C) The box with a mass of 6kg
![a =(8)/(6)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/xiqbf5b08rq7gd4ka9idawmvqi17tvpmda.png)
a = 1.33 m/s2
D) The box with a mass of 8kg
![a =(8)/(8)](https://img.qammunity.org/2021/formulas/chemistry/middle-school/8zuuygpn20m9qrh5smxa4lh3nrcj4fvqvp.png)
a = 1 m/s2