Answer:
A) The circumference of the tire is approximately 90.12 in.
B) Ann can travel a distance of
or
in one minute.
Explanation:
Given,
Diameter of the tire = 28.7 in
Solving for part A.
We have to find out the circumference of the tire.
Since the tire is in circular shape.
So the circumference of the tire is equal to π multiplied with diameter.
On framing the above sentence in equation form, we get;
![Circumference = \pi d](https://img.qammunity.org/2021/formulas/mathematics/high-school/zpg3nk8gpjojd4b5f44sav5iel34pjuzj7.png)
On putting the values, we get;
![Circumference = 3.14*28.7=90.118\approx90.12\ in](https://img.qammunity.org/2021/formulas/mathematics/high-school/m806vvgf1w9g39evazf8hhznou0nfkq7tk.png)
Hence The circumference of the tire is approximately 90.12 inches.
Solving for part B.
Now Given:
Number of revolutions = 270
Now we know that distance traveled is equal to circumference of the travel.
In 1 revolution = 90.12 inches
so in 270 revolutions = Distance traveled in 270 revolutions.
By Using Unitary method we get;
Distance traveled in 270 revolutions =
![90.12* 270 = 24332.4\ in](https://img.qammunity.org/2021/formulas/mathematics/high-school/ctshcwlrzbln157mlo6n0veyo54lrrcex0.png)
Now we know that 1 inch = 0.0254 m
So 24332.4 inch = Distance traveled in 1 minute
By Using Unitary method we get;
Distance traveled in 1 minute =
![0.0254* 24332.4 = 618.04\ m](https://img.qammunity.org/2021/formulas/mathematics/high-school/6z17hjvx1am3t0gxexpcoyiyqxpug3tnx1.png)
Hence Ann can travel a distance of
or
in one minute.