Answer:
![3(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/9d7e4tnrysryzb0bp8iu7kuvngyksxqa90.png)
Explanation:
Find the sum
![1(3)/(4) +1(5)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/so4gain1dh8nh60upuzm61smm1o24wi6en.png)
we know that
![(3)/(4)=(6)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cd75p6gs11vfsqpwtk1tdguyu83dqxcpu3.png)
substitute
![1(6)/(8) +1(5)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/cbuxawlk41c94jc6522vxcvnobrwz3f3ne.png)
step 1
Separate the mixed number into a whole number and a fraction number
![1+(6)/(8) +1+(5)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/axp6f52qy5h63avy5mmdm96aeqopr4i6vn.png)
step 2
Group the whole numbers an the fraction numbers
![(1+1)+((6)/(8) +(5)/(8))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/w6b6tfrifrbzbdfe7jdhyylkobd36uyenp.png)
step 3
Combine like terms
![(2)+((11)/(8))](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fpp12wf09h0lgq0kmkqxft7ejxfcjg1z8i.png)
Remember that
![(11)/(8)=(8)/(8)+(3)/(8)=1+(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8b39xau28g74zga9ctwce9fuzy81nbhy40.png)
substitute
![2+1+(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/8tb8x6bb7uyhlztc0fgs243j21lfc28rzc.png)
![3+(3)/(8)=3(3)/(8)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/y67fi1o6663ug5qofw75ohrhc6aensxw73.png)
The answer is reasonable
Because
I know that 1 3/4 < 2 and 1 5/8 < 2
so
The sum of both numbers must be less than 4