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What is the complete factorization of ×^2+4x-45​

2 Answers

2 votes

Answer:

Explanation:

ײ+4x-45​ = (x²+4x+4) - 4 -45

= (x+2)² - 7²

by identity : a²-b² = (a+b)(a-b

(x+2)² - 7² = (x+2-7)(x+2+7)

the factorization is :

ײ+4x-45​ = (x-5)(x+9)

User Anapsix
by
7.4k points
2 votes
=x^2+x(9-5)-45
=x^2+9x-5x-45
=x(x+9)-5(x-9)
=(x+9)(x-5)
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