Question

Helppp pleaseee anyone!

Answer 1

A)
`(x+2)(x+2)=0\\`

B)
`x=-2\ or\ x=-2`

C) { -2 , -2 }

Explanation:

Given:

`11x^(2)+44x+44=0`

To Find:

A) Factor the Trinomial.

B) use the zero product property

C) ordered pairs.

Solution:

A) Factor the Trinomial.

Dividing the given equation throughout by 11 we get

`(11x^(2))/(11)+(44x)/(11)+(44)/(11)=(0)/(11)`

`x^(2)+4x+4=0`

For factorizing remove the factor 4 such that on addition you will get 4

i.e 2 × 2 = 4 and 2 + 2 = 4

Now by splitting the middle term we get

`x^(2)+2x+2x+4=0\\x(x+2)+2(x+2)=0\\(x+2)(x+2)=0\\`

B) Using the zero product property and set each factor equal to 0 we get

`(x+2)(x+2)=0\\(x+2)=0\ or\ (x+2)=0\\x=-2\ or\ x=-2`

C) The solution written in the ordered pairs is

{ -2 , -2 }