Answer:
b)
is another zero of the polynomial
Explanation:
Since you are given a set of options to choose from, a very simple way to find the zero of the polynomial is by simply plugging each value from the options and seeing which of them gives the answer 0.

Using all the options:

Now we know that at x = -4 the value of the polynomial f(x) is 0. hence
b)
is another zero of the polynomial