Question

35. Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is ln y = 1.7 + .45x. What is the predicted value of y when x = .72?

Answer 1

`y=7.57`

Explanation:

Two variables, x and y, appear to be exponentially related. The regression equation for ln y on x is
`ln y = 1.7 + .45x`

we need to predict the value of y when x=0.72

plug in the value of x in the given equation

`ln y = 1.7 + .45x`

`ln y = 1.7 + .45(0.72)`

`ln y = 1.7 + 0.324`

`ln y = 2.024`

`y=e^(2.024)`

`y=7.57`