Answer:
Therefore
15.
![25c^(2)-9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gieohucu21hpq2rftryj2mvz75990z98mw.png)
16.
![(y+8)(y+1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6oj7eovy4hmv7q5scvmkf6i86synwr73vu.png)
17.
![(x-3y)(x-7y)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lvthb50gug56vpk53oxg8w0l2792abs6jk.png)
Explanation:
15.
![(5c^(2) +3)(5c^(2)-3)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/wha0325wcn4qnybhtmoqze8bqaac8c26sf.png)
Using the Identity (a + b)(a - b) = (a² - b²) we get
Consider here a = 5c and b = 3 then we will have
.....as required
16.
![y^(2)+9y+8](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ntkfh474elpw61mcjd3jpy8cedlzmipgr3.png)
Here Factorize 8 such that sum up to be 9
∴ 8 × 1 = 8 and 8 + 1 =9
... as required
17.
![x^(2)-10xy+21y^(2)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/ijpj27ksabb1p6h4iamcsbevyr7ill5j3c.png)
Here Factorize 21 such that sum up to be -10
∴ -3 × -7 = + 21 and -3 - 7 = - 10
........as required
Therefore
15.
![25c^(2)-9](https://img.qammunity.org/2021/formulas/mathematics/middle-school/gieohucu21hpq2rftryj2mvz75990z98mw.png)
16.
![(y+8)(y+1)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/6oj7eovy4hmv7q5scvmkf6i86synwr73vu.png)
17.
![(x-3y)(x-7y)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lvthb50gug56vpk53oxg8w0l2792abs6jk.png)