Question

Calculate the kinetic energy of a 8.8 x 10^13 kg comet moving at a speed of 33.0 km/s. Round your answer to 2 significant digits?

Answer 1

`KE=4.79* 10^(22)\ J`

Step-by-step explanation:

Given that

Mass ,m= 8.8 x 10¹³

Speed ,v= 33 km/s

We know that 1 km= 1000 m

v= 33 x 10³ m/s

As we know that kinetic energy given as

`KE=(1)/(2)mv^2`

Now by putting the values in the above equation

`KE=(1)/(2)* 8.8* 10^(13)* 33000^2`

`KE=4.7916* 10^(22)\ J`

Therefore we can say that the kinetic energy will be

`KE=4.79* 10^(22)\ J`