Answer:
Glucose present, lactose absent: transcription of the lac operon does not occur. That is because the lac repressor remains attached to the operator and prevents transcription by RNA polymerase. In addition, cAMP levels are low because glucose levels are high, so CAP is inactive and cannot bind to DNA.
_ Modified image of "Prokaryotic gene regulation: Figure 3", by OpenStax College, Biology (CC BY 4.0) ._
Glucose present, lactose present: transcription of the lac operon is given at a low level. The lac repressor is released from the operator because the inducer (alolactose) is present. CAMP levels, however, are low because there is glucose. Then, CAP remains inactive and cannot bind to DNA, so transcription only occurs at a low or poor level.
Glucose present, lactose present: low level transcription of operon * lac * occurs. The * lac * repressor is released from the operator because the inducer (alolactose) is present. CAMP levels, however, are low because glucose is present. So, CAP remains inactive and cannot bind to DNA, so transcription only occurs at a low or poor level.
Glucose present, lactose present: low level transcription of the lac operon occurs. The lac repressor is released from the operator because the inducer (alolactose) is present. CAMP levels, however, are low because glucose is present. So, CAP remains inactive and cannot bind to DNA, so transcription only occurs at a low or poor level.
_ Modified image of "Prokaryotic gene regulation: Figure 3", by OpenStax College, Biology (CC BY 4.0) ._
Glucose absent, lactose absent: transcription of the lac operon does not occur. CAMP levels are high because glucose levels are low, so CAP is active and will be bound to DNA. However, the lac repressor will also be attached to the operator (due to the absence of alolactose), and acts as a barrier to RNA polymerase and prevents transcription.
Glucose absent, lactose absent: transcription of operon * lac * does not occur. CAMP levels are high because glucose levels are low, so CAP is active and will be bound to DNA. However, the * lac * repressor will also be linked to the operator (due to the absence of alolactose), so it acts as a barrier to RNA polymerase and prevents transcription.
Glucose absent, lactose absent: transcription of the lac operon does not occur. CAMP levels are high because glucose levels are low, so CAP is active and will be bound to DNA. However, the lac repressor will also be linked to the operator (due to the absence of alolactose), so it acts as a barrier to RNA polymerase and prevents transcription.
_ Modified image of "Prokaryotic gene regulation: Figure 3", by OpenStax College, Biology (CC BY 4.0) ._
Glucose absent, lactose present: a strong transcription of the lac operon occurs. The lac repressor is released from the operator because the inducer (alolactose) is present. CAMP levels are high because there is no glucose, so CAP is active and bound to DNA. CAP helps RNA polymerase bind to the promoter, allowing high levels of transcription