Question

Find the solutions to x2-12x+36=0

Answer 1

The solution is x=6

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`x^(2) -12x+36=0`

so

`a=1\\b=-12\\c=36`

substitute in the formula

`x=\frac{-(-12)\pm\sqrt{-12^(2)-4(1)(36)}} {2(1)}`

`x=\frac{12\pm√(0)} {2}`

`x=\frac{12} {2}=6`