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A student runs 3 1/3 miles in 30 minutes. A teacher runs 1 1/4 times as far in 30 minutes. How far can the teacher run in 30 minutes?

User Schmalzy
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1 Answer

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Answer:

The distance cover by teacher in 30 minutes is 4
(1)/(6) miles .

Explanation:

Given as :

The distance cover by student = d = 3
(1)/(3) miles

i.e d =
(10)/(3) miles

The time taken by student to cover
(10)/(3) miles distance = t = 30 minutes

Let The speed of student = s miles per minute

Speed =
(\textrm Disatnce)/(\textrm Time)

Or, s =
(d)/(t)

Or, s =
((10)/(3))/(30)

i.e s = 0.111 miles per min

So, The speed of student = s = 0.111 miles per min

Now, Again

The speed of teacher = 1
(1)/(4) times as fast as student

Let The speed of teacher = S miles per min

∵ The speed of teacher =
(5)/(4) × speed of student

So, S =
(5)/(4) × s

Or, S =
(5)/(4) × 0.111 miles per min

Or, S =
(5* 0.111)/(4) mil/min

i.e, S = 0.13875 miles per min

So, The speed of teacher = S = 0.13875 miles per min

Let The distance cover by teacher = D miles

The time taken by teacher to cover D miles distance = T = 30 minutes

Distance = Speed × Time

Or, D = S × T

Or, D = 0.13875 miles per min × 30 min

∴ D = 4.1625 miles

i.e D = 4
(1)/(6) miles

So, The distance cover by teacher in 30 minutes = D = 4
(1)/(6) miles

Hence,The distance cover by teacher in 30 minutes is 4
(1)/(6) miles . Answer

User Beslan Tularov
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