Answer:
Molarity = 0.650 M
Normality = 1.30 N
Step-by-step explanation:
In case of titration , the following formula can be used -
M₁V₁ = M₂V₂
where ,
M₁ = concentration of acid ,
V₁ = volume of acid ,
M₂ = concentration of base,
V₂ = volume of base .
from , the question ,
M₁ = ? M
V₁ = 25.05mL
M₂ = 0.210 M
V₂ = 77.60 mL
Using the above formula , the molarity of acid , can be calculated as ,
M₁V₁ = M₂V₂
M₁ * 25.05mL = 0.210 M * 77.60 mL
M₁ = 0.650 M
Hence, the molarity of the acid = 0.650 M
Normality of a diprotic acid can be calculated by multiplying 2 with the value of molarity ,
Hence,
Normality = M * 2 = 0.650 * 2 = 1.30 N