Question

If you had 10.00 mL of acetic acid that you titrated with .100 M NaOH, and you used 45.15 mL of that base to get a light pink color, what is the concentration of your acetic acid?

A) .904M
B) .452M

Answer 1

0.4515 M

Step-by-step explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 10.0 mL

M₂ = 0.100 M

V₂ = 45.15 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 10.0mL = 0.100 M * 45.15 mL

M₁ = 0.4515 M

Hence, the concentration of the acetic acid = 0.4515 M