Question

A scuba diver, submerged under water looks up and seessunlight

at an angle of 30 degrees from the vertical. Atwhat
angle measured from the vertical does the sunlight strike
thesurface of the water? Assume water has a refraction index
of1.333.

Answer 1

`41.7975\ ^(\circ)`

Step-by-step explanation:

`n_2` = Refraction index of water = 1.333

`n_1` = Refraction index of air = 1

`\theta_2` = Angle of sunlight = 30°

From Snell's law we have

`(n_1)/(n_2)=(sin\theta_2)/(sin\theta_1)\\\Rightarrow \theta_1=sin^(-1)(n_2sin\theta_2)/(n_1)\\\Rightarrow \theta_1=sin^(-1)(1.333sin30)/(1)\\\Rightarrow \theta_1=41.7975\ ^(\circ)`

The angle measured from the vertical does the sunlight strike thesurface of the water is
`41.7975\ ^(\circ)`