during this reaction, p4+502 p4010 0.800 moles of product was made in 30 sec. what is the rate of reaction

asked Mar 27, 2021 107k views

5 votes

by EeKay

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4 votes

Answer:

Rate of reaction is : 0.027 mol/Ls.

Step-by-step explanation:

$P_(4) + 5 O_(2) \rightarrow P_(4)O_(10)$

$rate = +(1)/(1)(\Delta [P_(4)O_(10)])/(\Delta t)$

${\Delta t} = 30 sec$

$\Delta [P_(4)O_(10)] = 0.8$

rate = +(1)/(1)(0.8)/(30)

rate = 0.027 mol/Ls

rate = 0.027 moleL^(-1)s^(-1)

Zohaib Ijaz answered Apr 3, 2021

6.7k points

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