Question

A ship traveling east at 25 mph is 10 miles from the harborwhen a

second ship leaves the harbor traveling east at 35 mph. Howlong
will it take the second ship to catch up with the firstship?

Answer 1

Time taken by second ship to catch up first is 1 hour

Explanation:

Let the distance of the destination from the harbor is x

It is given that first ship is 10 miles from the harbor 'So distance traveled by first ship = x - 10

Speed = 25 mph

So time taken taken
`=(x-10)/(25)`

And time taken by second ship to reach the destination
`=(x)/(35)`

Now
`(x-10)/(25)=(x)/(35)`

`35x-350=25x`

`x=35mile`

So time taken by second ship will be equal to
`(35)/(35)=1hour`