Question

Example 2
What is the center and radius of the following circle?
x^2+4x+y^2−12y=41.

Answer 1

center (2,6)

radius = 3

Explanation:

good luck :)

Answer 2

The answer to your question is below

Explanation:

x² + 4x + y² - 12y = 41

Complete perfect squares

x² + 4x + y² - 12y = 41

x² + 4x + (2)² + y² - 12y + (6)² = 41 + (2)² + (6)²

Factor

(x + 2)² + (y - 6)² = 41 + (2)² + (6)²

Simplify

(x + 2)² + (y - 6)² = 41 + 4 + 36

(x + 2)² + (y - 6)² = 81

Center = (-2, 6)

Radius =
`√(81) = 9`