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1 vote
What is the product?

StartFraction 5 k Over 6 EndFraction times StartFraction 3 Over 2 k cubed EndFraction
StartFraction 5 Over 4 k squared EndFraction
StartFraction 5 k squared Over 4 EndFraction
StartFraction 5 k Superscript 4 Baseline Over 4 EndFraction
StartFraction 5 Over 4 k Superscript 4 Baseline EndFraction

2 Answers

4 votes

Answer:

a

Explanation:

User Robmclarty
by
5.6k points
2 votes

Answer:

StartFraction 5 Over 4 k squared EndFraction

Explanation:

We are asked to find the next product:


(5 k)/(6) * (3)/(2 k^3)

Dividing numerator and denominator by k:


(5 (k)/(k))/(6) * (3)/(2 (k^3)/(k))


(5)/(6) * (3)/(2 k^2)

Dividing numerator and denominator by 3:


(5)/((6)/(3)) * ((3)/(3))/(2 k^2)


(5)/(2) * (1)/(2 k^2) = (5)/(4 k^2)

User Kishan Vaghela
by
5.3k points