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What is the mass in grams of 2.30 x10^23 molecules of Fluorine

User PVCS
by
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1 Answer

4 votes

Answer:

14.512g

Step-by-step explanation:

Using the expression

mole = Number of molecules/6.022 x 10^23

mole of Fluorine = 2.30 x10^23/6.022 x 10^23

= 0.3819 mol

However,

mole = mass / molarmass

Mass of Fluorine = mole of Fluorine/ Molarmass of Fluorine

Molarmass of Fluorine = 18.998 x 2 = 37.996 g/mol

Mass of Fluorine = 0.3819mol/37.996g/mol

= 14.512g

User Peter Zhang
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