Question

Number 20! Please help thank you!!!

Answer 1

`x=6`

Explanation:

we know that

If SQ is an angle bisector

then

`m\angle TSQ=m\angle QSR`

we have

`m\angle TSQ=(5x+3)^o`

`m\angle OSR=(10x-27)^o`

substitute the given values

`(5x+3)^o=(10x-27)^o`

solve for x

Group terms

`10x-5x=3+27`

Combine like terms

`5x=30`

Divide by 5 both sides

`x=6`