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The quotient of (x^4 + 5x^3– 3x – 15) and a polynomial is (x^3 - 3). What is the polynomia

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The missing polynomial must be of degree 1, since the dividend has degree 4 and the divisor has degree 3. So we're looking for a polynomial
ax+b such that


(x^3-3)(ax+b)=x^4+5x^3-3x-15

Expanding the left hand side gives


ax^4+bx^3-3ax-3b

We need to have


\begin{cases}ax^4=x^4\\bx^3=5x^3\\-3ax=-3x\\-3b=-15\implies a=1,b=5

so that the missing polynomial is
\boxed{x+5}.

User Alessandro
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