Question

Plant b is 6 2/3 inches tall. Plant c is 4 4/15 inches tall. Plant c is _____ times as tall as plant b.

Answer 1

Answer:16/25

Explanation:

Answer 2

Plant c is
`((16)/(25))` times as tall as plant b.

Explanation:

Here, the length of the plant b =
`6(2)/(3)` inches

Solving the mixed fraction, we get:

`6(2)/(3)  = ((6 * 3) + 2)/(3)  = (20)/(3)`

So, the length of plant b =
`(20)/(3)` inches

Also, the length of the plant c =
`4(4)/(15)` inches

Solving the mixed fraction, we get:

`4(4)/(15)  = ((15 * 4) + 4)/(15)  = (64)/(15)`

So, the length of plant c =
`(64)/(15)` inches

Now, let us assume that:

Plant c = K times as tall as plant b.

or, Length of plant c = K x ( Length of plant b)

`\implies ((64)/(15))  = K * ((20)/(3))\\\implies K = ((64)/(15)) * ((3)/(20))  = ((16)/(25))\\\implies K =  ((16)/(25))`

Hence, Plant c is
`((16)/(25))` times as tall as plant b.