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I will be truly gratefully for however helps me.
Please i'm in need of help.

I will be truly gratefully for however helps me. Please i'm in need of help.-example-1
User Yjshen
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1 Answer

1 vote

Answer:

a) x = 45°

b) AD is parallel to BC.

Explanation:

Here, the given angles in the quadrilateral ABCD are:

∠A = ( 2 x)° , ∠B = ( 90)° , ∠C = ( x)° and ∠D = ( 3x)°

Now, in a quadrilateral: SUM OF ALL INTERIOR ANGLES IS 360°.

∠A+ ∠B+ ∠C +∠D = (180)°

or, ( 2 x)+ ( 90)° + ( x)° + ( 3x)° = (180)°

or, 6 x = 180 - 90 = 270°

or, x = 270/6 = 45°

or, x = 45°

Now, ∠A = ( 2 x)° = 2 x (45°) = 90°

⇒∠A = ∠B = 90°

So, AD and BC are two lines perpendicular to AB.

⇒ AD II BC (as two liner PERPENDICULAR to the same given lines are PARALLEL to each other)

Hence, AD is parallel to BC.

User AnandShiva
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