Question

A circle with center C (4, -2) contains the point D(8,1) what is the equation for the line perpendicular to the radius of the circle passing through point C

Answer 1

Explanation:

slope of line passing through C and D is

`m=(1+2)/(8-4) =(3)/(4) \\`

slope of line perpendicular to CD=-4/3

reqd. eq. of line through C(4,-2) is

`y+2=-(4)/(3) (x-4)\\3y+6=-4x+16\\4x+3y=10`