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Subtract the sum of x2−3xy−y2 and 2x2+5xy−4y2 from 6x2−7xy+8y2

User Nese
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2 Answers

4 votes

Answer:

Answer in image

Explanation:

Answer in image

Subtract the sum of x2−3xy−y2 and 2x2+5xy−4y2 from 6x2−7xy+8y2-example-1
User Nikos Athanasiou
by
7.0k points
4 votes

Answer:


3x^2-9xy+13y^2

Explanation:

We begin with :
6x^2-7xy+8y^2-[(x^2-3xy-y^2)+(2x^2+5xy-4y^2)]

First, let us add the two portions within the brackets. To do this, we need to just combine the like terms


6x^2-7xy+8y^2-[(x^2-3xy-y^2)+(2x^2+5xy-4y^2)]\\\\6x^2-7xy+8y^2-[3x^2+2xy-5y^2]

Next, we need to distribute the negative to all the terms within the brackets


6x^2-7xy+8y^2-[3x^2+2xy-5y^2]\\\\6x^2-7xy+8y^2-3x^2-2xy+5y^2

Now we can combine the like terms again


6x^2-7xy+8y^2-3x^2-2xy+5y^2\\\\3x^2-9xy+13y^2

User Oana
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6.3k points